00:01
In this question, you are giving graph that shows a position versus time for mass oscillating on a spring.
00:07
So it's harmonic oscillations.
00:09
You're asked to estimate the phase constant if the expression, i mean, the dispersing the excess function is given by a cosine omega -t plus five.
00:23
You ask to estimate this five, right? first, you notice that from this graph is clear, from this graph is clear that the amplitude of the oscillation is just two, right? two meters.
00:36
So, a equals two.
00:37
So you can write a two cosine omega -t plus five.
00:42
Now, at t equals zero, at t equals zero, so at t equals zero, you get the, the disbursement is one, right? so it's one.
00:54
At t equals zero, the disperiment is one.
00:56
1 and equals 2 cosine 5.
01:00
And from that, you see that cosine 5 equals 1 over 2, so 5 must be 60 degrees.
01:12
The second question asks, at what position is the potential energy u or of a mass on the spring, undergoing simple harmonicalization motion equal to 1 third of the kinetic energy stored in spring? you know, the total energy is simply given by k, which is the spring constant times a squared divided by two.
01:35
That's a total potential energy...
