Question

(a) The work function of potassium is 2.3 eV. Light of wavelength 250 nm falls on the potassium, find i. the stopping potential in volts , ii. the kinetic energy in electron volts of the fastest electrons ejected, iii. and the speed of these electrons. iv. What wavelength of light would be needed to obtain double the speed?

          (a) The work function of potassium is 2.3 eV. Light of wavelength 250 nm falls on the potassium, find
i. the stopping potential in volts ,
ii. the kinetic energy in electron volts of the fastest electrons ejected,
iii. and the speed of these electrons.
iv. What wavelength of light would be needed to obtain double the speed?

(a) The work function of potassium is 2.3 eV. Light of wavelength 250 nm falls on the potassium, find
i. the stopping potential in volts ,
ii. the kinetic energy in electron volts of the fastest electrons ejected,
iii. and the speed of these electrons.
iv. What wavelength of light would be needed to obtain double the speed?

Added by Dawn F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/15/2024

Step 1

First, we need to find the energy of the incident light. We can use the formula: E = \frac{hc}{\lambda} where E is the energy, h is Planck's constant (6.63 x 10^{-34} Js), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength (250 nm = 250 x 10^{-9} Show more…

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(a) The work function of potassium is 2.3 eV. Light of wavelength 250 nm falls on the potassium, find i. the stopping potential in volts, ii. the kinetic energy in electron volts of the fastest electrons ejected, iii. and the speed of these electrons. iv. What wavelength of light would be needed to obtain double the speed?