Question

A thin, nonconducting disk of radius R is free to rotate around the axis that passes through its center and is perpendicular to the face of the disk . The disk is charged uniformly with a total charge q. The disk rotates at a constant angular velocity ?. (a) What is the magnetic field at the center of the disk? (b) Find an expression for the total magnetic moment of the spinning disk. (c) Taking R=0.125 m, q = 3.6 mC, and ? = 377 rad/s, calculate the potential energy of the spinning disk when it is placed in a uniform magnetic field of 1.25 T that is at an angle of 60° with respect to the axis of the spinning disk.

          A thin, nonconducting disk of radius R is free to rotate around the axis that passes through its center and is perpendicular to the face of the disk . The disk is charged uniformly with a total charge q. The disk rotates at a constant angular velocity ?.
(a) What is the magnetic field at the center of the disk?
(b) Find an expression for the total magnetic moment of the spinning disk.
(c) Taking R=0.125 m, q = 3.6 mC, and ? = 377 rad/s, calculate the potential energy of the spinning disk when it is placed in a uniform magnetic field of 1.25 T that is at an angle of 60° with respect to the axis of the spinning disk.

A thin, nonconducting disk of radius R is free to rotate around the axis that passes through its center and is perpendicular to the face of the disk . The disk is charged uniformly with a total charge q. The disk rotates at a constant angular velocity ?.
(a) What is the magnetic field at the center of the disk?
(b) Find an expression for the total magnetic moment of the spinning disk.
(c) Taking R=0.125 m, q = 3.6 mC, and ? = 377 rad/s, calculate the potential energy of the spinning disk when it is placed in a uniform magnetic field of 1.25 T that is at an angle of 60° with respect to the axis of the spinning disk.

Added by Frank N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

06/10/2022

Step 1

Step 1:** The expression for the magnetic field at the center of the disk is given by: \[ B = \mu_0 \sigma \omega R / 2 \] ** Show more…

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A thin, nonconducting disk of radius R is free to rotate around the axis that passes through its center and is perpendicular to the face of the disk. The disk is charged uniformly with a total charge q. The disk rotates at a constant angular velocity ω. (a) What is the magnetic field at the center of the disk? (b) Find an expression for the total magnetic moment of the spinning disk. (c) Taking R=0.125 m, q = 3.6 mC, and ω = 377 rad/s, calculate the potential energy of the spinning disk when it is placed in a uniform magnetic field of 1.25 T that is at an angle of 60° with respect to the axis of the spinning disk.