The torque is given by the formula:
$\tau = rF\sin\theta$
For force F, the distance r from the axis is 3m, and the angle $\theta_1 = 36.879^\circ$. So the torque produced by force F is:
$\tau_F = 3 \times 720 \times \sin(36.879^\circ)$
For force E, the
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