A thin rod is pivoted around its end, and an identical rod around its center. If they are to have the same rotational kinetic energy, then \omega_{end}/\omega_{center} = Multiple Choice 1/2 1/4 2 1 4
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Step 1: The rotational kinetic energy of a rigid body is given by $KE_{rot} = \frac{1}{2}I\omega^2$, where $I$ is the moment of inertia and $\omega$ is the angular velocity. Show more…
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A slender metal rod has a mass $M$ and length $L$. The rod is first rotated about a perpendicular axis through its center with an angular velocity $\omega$ (Figure $9.28 \mathrm{a}$ ). It is then rotated about a perpendicular axis through its end at the same angular velocity (Figure $9.28 \mathrm{~b}$ ). Find the ratio of the kinetic energy of the first case to that of the second case.
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