Question

A thin rod with length \( L=2 \mathrm{~m} \) and negligible mass, has a ball of mass \( m=1 \mathrm{~kg} \) attached to the end. The ball is at rest when the rod makes an angle of \( 45^{\circ} \) with the vertical. What is the velocity of the pendulum at the bottom? \( \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2} \)

Name: A thin rod with length L=2 m and negligible mass, has a ball of mass m=1 kg attached to the end. The ball is at rest when the rod makes an angle of 45^∘ with the vertical. What is the velocity of the pendulum at the bottom? g=9.8 m / s^2
Uploaded: 2023-07-11T14:24:39-08:00
Duration: 8 min 34 s
Channel: Vishal Gupta
Description: A thin rod with length L=2 m and negligible mass, has a ball of mass m=1 kg attached to the end. The ball is at rest when the rod makes an angle of 45^∘ with the vertical. What is the velocity of the pendulum at the bottom? g=9.8 m / s^2

          A thin rod with length \( L=2 \mathrm{~m} \) and negligible mass, has a ball of mass \( m=1 \mathrm{~kg} \) attached to the end. The ball is at rest when the rod makes an angle of \( 45^{\circ} \) with the vertical. What is the velocity of the pendulum at the bottom? \( \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2} \)

A thin rod with length L=2 m and negligible mass, has a ball of mass m=1 kg attached to the end. The ball is at rest when the rod makes an angle of 45^∘ with the vertical. What is the velocity of the pendulum at the bottom? g=9.8 m / s^2

Added by Gregory H.

University Physics Volume 1

Samuel J. Ling, Jeff Sanny, William… 1st Edition

Chapter 10

Instant Answer

Solved by Expert Vishal Gupta

07/11/2023

Step 1

The initial position is when the rod makes a \(45^\circ\) angle with the vertical, and the final position is at the bottom of the swing. Show more…

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A thin rod with length \( L=2 \mathrm{~m} \) and negligible mass, has a ball of mass \( m=1 \mathrm{~kg} \) attached to the end. The ball is at rest when the rod makes an angle of \( 45^{\circ} \) with the vertical. What is the velocity of the pendulum at the bottom? \( \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2} \)