00:01
Hi friends, given a thin rod of length 4 meter and mass 3 kg.
00:19
It is rotating about the axis a which is passing through 1 meter from the one end and at vertical position it having the kinetic energy 20 jude.
00:47
We have to find moment of inertia about the axis a.
00:54
We have to find the velocity of viii.
00:57
At vertical position and theta it rotate above to the vertical position this will be the position of center of mass 2 meter moment of inertia of the rod about axis a will be moment of inertia about center of mass plus m into h square that is m l square by 12 plus m into h square substituting the value, mass of the rod is given 3kg, length is 4 upon 12 plus 3 into 1 square.
02:02
So it is to be 7 kg meter square.
02:10
Now kinetic energy of rotation is defined as half i omega square.
02:16
This is given 20.
02:19
So angular velocity of rotation you will get 2 .39 radian per second.
02:31
So angular velocity of b point will be omega into length of av 2 .39 into 3.
02:45
That is 7 .17 meter per second...