A thin wall tube with closed ends is made from steel with a yield strength of 250 MPa. The tube is 2 m long with a wall thickness of 2 mm and a diameter of 8 cm. In service it will experience an axial load of 8 kN and a torque of 2.7 Nm. What is the maximum internal pressure it can withstand without yielding according to (a) the Tresca criterion and (b) the von Mises criterion?
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The axial stress (σ) due to the axial load (F) can be calculated using the formula: σ = F / A where A is the cross-sectional area of the tube. The cross-sectional area can be calculated using the formula: A = π * (D^2 - d^2) / 4 where D is the outer diameter Show more…
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