00:01
Hello students in this question given as a three impedance z1, z2 and z3 which are connected in parallel.
00:06
The value of z1 impedance is given as 25 magnitude and angle is 15 degree.
00:17
This we can write as 25 cos of 15 degree plus j 25 sin of 15 degree.
00:30
This is the explanation of this z1 and z2 is given as 1560 degree and z3 is given as 1590 degree.
00:48
And the voltage applied voltage is 339 .4 and angle there is minus 30 degree.
00:58
This is the volt and all the quantities are in ohm impedance.
01:04
So now we know that the z1, z2, z3 are in parallel.
01:09
So we will write equivalent z is equal to z1 parallel with z2 parallel with z3.
01:19
Now we can write z1 in parallel in bracket z2 and z3 in parallel.
01:25
So we can write here 1560 degree 1590 degree 1590 degree upon z1 z2 plus z3 60 degree plus 90 degree.
01:57
Now after calculation this will be equal to the z1 in parallel in bracket.
02:03
The value is 7 .76 angle 75 degree.
02:11
Now we can write again z1 and this value is in parallel.
02:16
So 25 15 degree into 7 .6 7 6 5 75 degree upon 25 15 degree plus 7 .76 75 degree.
02:41
After calculation z will be equal to the 6 .54 61 .9 degree.
02:51
Now the flowing current in the circuit will be equal to the v upon z...