00:01
In this question we have the value of a supply voltage, vl which is equal to 400 watt.
00:07
Then the frequency f which is equals to 50 hertz.
00:11
Next we have the number of poles that is p which is equals to 4.
00:17
Now we can also write down the equation for the synchronization speed that is ns which is equals to 120 f divided by p so here we have this 120 frequency that is a 50 divided by number of poles that is 4 so on a simplification of it we get the value of ns which is equals to 1 5 or 0 this is in rpm now we also have the sleep s which is equals to 0 .04 we can write down the value of resistor r1 which is equal to point of 15 om, then x1 which is equals to x2, which is equals to 0 .45 om, r2 which is equal to 0 .12 oom, and xm, which is equal to 28 .5 oom.
01:20
Now let's first to draw the circuit.
01:23
So this is the equivalent.
01:29
Equivalent circuit, circuit referred to stator.
01:42
Now we can write down the equation of r -dash -l which is equal to r2 multiplied by 1 divided by s minus of 1.
01:51
Now let's further simplify it.
01:54
So it becomes 0 .12 multiplied by 24.
01:58
So on a further simplification we get the value of a rl dash which is equal to 2 .88 o.
02:07
Then current i note which is equal to v, ph divided by xm.
02:14
So it becomes 400 divided by root 3 divided by this xm we have 28 .5.
02:26
So on a simplification, here this xm has a vector j.
02:31
So it becomes minus 8 .103j.
02:39
Now on a further simplification, we can find out the value of i2 dash, that is the vp divided by r note 1 plus rl dash multiplied by plus jx01.
02:56
So we can write this as vp divided by r1 plus r1 plus r1 plus jxo1...