Question

A time-domain OCT system uses a low-coherence light source. The central wavelength is 1300 nm. If we want to design a system with an axial resolution finer than 15 μm, please determine the minimum linewidth.

          A time-domain OCT system uses a low-coherence light source. The central wavelength is 1300 nm. If we want to design a system with an axial resolution finer than 15 μm, please determine the minimum linewidth.
        

Added by Tara H.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
A time-domain OCT system uses a low-coherence light source. The central wavelength is 1300 nm. If we want to design a system with an axial resolution finer than 15 μm, please determine the minimum linewidth.
Close icon
Play audio
Feedback
Powered by NumerAI
Jennifer Stoner Danielle Fairburn
Ivan Kochetkov verified

Sri K and 74 other subject Physics 103 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
the-human-eye-can-readily-detect-wavelengths-from-about-400-nm-to-700-nm-if-white-light-illuminates-a-diffraction-grating-having-890-linesmm-over-what-range-of-angles-does-the-visible-m-1-sp-28195

The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating having 890 lines/mm, over what range of angles does the visible m = 1 spectrum extend? θmin, θmax

Sri K.

the-coherence-length-of-an-ordinary-white-light-source-can-be-increased-if-we-place-a-color-filter-in-front-of-the-source-so-that-the-light-that-passes-through-the-filter-is-somewhat-monochr-37058

The coherence length of an ordinary white light source can be increased if we place a color filter in front of the source, so that the light that passes through the filter is somewhat monochromatic. The minimum wavelength of the emerging light is 564 nm. What is the maximum wavelength in order for the coherence length to be 0.09900 mm?

Narayan H.

white-light-400-to-700-nm-is-used-to-illuminate-a-double-slit-with-a-spacing-of-125-mm-an-interference-pattern-is-observed-on-a-screen-placed-15-m-away-a-small-hole-located-3-mm-above-the-wh-87168

White light (400 to 700 nm) is used to illuminate a double slit with a spacing of 1.25 mm. An interference pattern is observed on a screen placed 1.5 m away. A small hole located 3 mm above the white central stripe allows a small portion of the pattern to be analyzed by a high resolution spectrograph. What wavelengths will be absent in the portion of light analyzed by the spectograph?

Hunza G.


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,793 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,157 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,529 solutions

*

Transcript

-
00:01 In this question the range of the wavelength is given in which the minimum wavelength we will take is lambda 1 is given which is 400 nanometer so we can convert this into millimeter then it will become 0 .004 millimeter then the maximum wavelength is given which is lemra 2 this will be equal to the 700 nanometer we can write this into nanometer then it will become 0 .007 millimeter then the diffraction grating is given which is equal to 890 lines per m m m so we can find the value of the the value of slit separation.
01:14 This can be found by small d.
01:18 It will become 1 mm divided by 890 lines.
01:29 And the order is given which is m is equal to 1 for the construct.
01:37 Interference we know that d sine theta for the constructive diffraction we know that the equation d sine theta is equal to m lambda m is equal to 1 so we can write d sine theta this will be equal to lambda we have to find the value of the angle so sine theta will equal to the lambda by d so we can write this diffraction angle theta will equal to the sine inverse of lambda by d.
02:16 So first we will find the minimum value.
02:21 So the minimum value of the theta will equal to sine inverse of lambda 1 divided by d...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever