00:01
The question is saying that there is a reaction taking place between one chloro, one methylome, one methylhexane, cydoxane along with k -o -h and as a result of which it is ethanolic k -o -h and as a result of it, what we obtain are two alkene.
00:29
That is asking us that how with the help of decoupled c -13 nmr spectra we can distinguish between the two compounds? let us look into it.
00:55
The equation that would be formed will be as follows.
01:10
Aethonolic k -o -h, it forms two compounds.
01:17
The first compound, o .s.
01:19
Number one and the second compound that gets formed will be as follows.
01:26
These are two different elkin that are produced by the reaction of one chloro, one methyl cyclohexane along with ethenolic k -oach.
01:37
Now we have to decipher the decoupled using the decoupled c3 13 nmr spectra how to distinguish between this compound.
01:46
Let us look into it.
01:47
When you talk about this first product, this is double bond.
01:58
Let's draw it once again.
02:09
And this is the second compound...