A town has two fire engines operating independently. The probability that a specific engine is available when needed is 0.88. (a) What is the probability that neither fire engine is available when needed? (b) What is the probability that a fire engine is available when needed?
Added by Daniel W.
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Given that the probability of a specific fire engine being available when needed is 0.88, we can use the binomial probability formula: P(X = 0) = C(2, 0) * (0.88)^0 * (1 - 0.88)^(2-0) P(X = 0) = 1 * 1 * 0.12^2 P(X = 0) = 1 * 1 * 0.0144 P(X = 0) = 0.0144 Show more…
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