00:01
Here in this question we need to find out the empirical formula of the compound.
00:09
Empirical formula of the compound.
00:13
And the given values is all about the mass of carbon dioxide and the total mass of the sample.
00:21
And it is mentioned that the amount of h2 as well.
00:28
13 .90 milligram of carbon dioxide.
00:32
These are the values which is mentioned in the question.
00:37
6 .048 milligrams of h2o and the combustion analysis of the sample, the mass of sample, which is equal to 5 .024 milligram of sample.
00:53
And these are the values which is mentioned in the question.
00:56
So using this, we can easily find out the number of, we need to calculate the number of of carbon, number of more of hydrogen, and number of moles of nitrogen as well.
01:07
Okay, so let's do the calculation and so that from the mass of carbon dioxide we can easily find out the number of more of carbon.
01:19
Let's do the calculation as well.
01:21
From carbon dioxide we can write that 13 .90 gram of carbon dioxide divided by its molar mass, that is 44 .01 gram of wall, which is equal to 0 .31583 moles of carbon dioxide.
01:45
And this will be equal to the number of more of carbon asper, 3153, moles of carbon.
01:53
Now this is the number of mores of carbon...