Question

A transistor radio operates by means of a 9.00 V battery that supplies it with 0.0500 A of current. a) What is the power of the radio in watts? b) The battery cost is unfortunately $9.00 per kilowatt-hour. The same radio, by means of a converter, is plugged into a household circuit by a homeowner who pays 5.00¢ per kilowatt-hour. Compute the cost of operating the radio for 300 hours on battery power, and then compute the cost using house current.

Name: a transistor radio operates by means of a 900 v battery that supplies it with 00500 a of current a what is the power of the radio in watts b the battery cost is unfortunately 900 per kilowat 46724
Uploaded: 2022-02-23T14:00:52-08:00
Duration: 2 min 33 s
Channel: Maardava V
Description: a transistor radio operates by means of a 900 v battery that supplies it with 00500 a of current a what is the power of the radio in watts b the battery cost is unfortunately 900 per kilowat 46724

          A transistor radio operates by means of a 9.00 V battery that supplies it with 0.0500 A of current.

a) What is the power of the radio in watts?
b) The battery cost is unfortunately $9.00 per kilowatt-hour.
The same radio, by means of a converter, is plugged into a household circuit by a homeowner who pays 5.00¢ per kilowatt-hour.
Compute the cost of operating the radio for 300 hours on battery power, and then compute the cost using house current.

Added by Philip W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Maardava V

02/23/2022

Step 1

Given: Voltage (V) = 9.00 V, Current (I) = 0.0500 A Power (P) = Voltage (V) x Current (I) P = 9.00 V x 0.0500 A P = 0.4500 W Show more…

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A transistor radio operates by means of a 9.00 V battery that supplies it with 0.0500 A of current. a) What is the power of the radio in watts? b) The battery cost is unfortunately $9.00 per kilowatt-hour. The same radio, by means of a converter, is plugged into a household circuit by a homeowner who pays 5.00¢ per kilowatt-hour. Compute the cost of operating the radio for 300 hours on battery power, and then compute the cost using house current.