A truck covers 40.0 m in 7.30 s while uniformly slowing down to a final velocity of 3.45 m/s. (a) Find the truck's original speed. m/s (b) Find its acceleration. m/s2
Added by Amparo J.
Step 1
0 m\) \(t = 7.30 s\) \(V_f = 3.45 m/s\) Plugging in the values: \(V_i = \frac{2 \times 40.0}{7.30} - 3.45\) Show more…
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