A truck moving initially at 24.6 m/s covers 70.0 m in 2.40 s. What is the truck's final speed?
Added by Michael B.
Step 1
6 \, m/s \times 2.4 \, s)}{(2.4 \, s)^2}\] \[a = \frac{2 \times (70 \, m - 58.8 \, m)}{5.76 \, s^2}\] \[a = \frac{2 \times 11.2 \, m}{5.76 \, s^2}\] \[a = \frac{22.4 \, m}{5.76 \, s^2}\] \[a \approx 3.89 \, m/s^2\] ** Show more…
Show all steps
Your feedback will help us improve your experience
Nishant Kumar and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A truck covers 40.0 m in 7.80 s while uniformly slowing down to a final velocity of 2.25 m/s. (a) Find the truck's original speed.
Adi S.
A truck covers 40.0 m in 8.50 s while uniformly slowing down to a final velocity of2.80 m/s. Find the truck’s original speed.
Nishant K.
A pickup truck pulling a trailer accelerates at $3.25 \mathrm{~m} / \mathrm{s}^{2}$ for $5.80 \mathrm{~s}$. If it starts from rest, what is its final velocity?
Motion
Acceleration
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD