A truncated cone of length L cm traveling through a fluid at...

A truncated cone of length L cm traveling through a fluid at a speed of 8.41 m/s is shown. The narrow end of the cylinder has a diameter of 2.22cm, whereas the wider end has a diameter of 3.37 cm. The drag force acting on the cylinder is 26.6 newtons. v The drag force Fd acting on an object passing through a fluid is given by Fd = 1/2?A?v^2 where A is the effective cross-sectional area of the object, ? (the Greek letter gamma) is the drag coefficient, ? is the density of the fluid, and v is the speed of the object. Calculate the drag coefficient ? of the object if the fluid is water of density 1000.00 kg/m^3. ? =

Transcript

00:01 In this question we are given here truncated cone of length l so here we are given here truncated here we have truncated cone of length truncated cone of length which is equal we can vent l centimeter and here in the l centimeter traveling to a fluid this p v which is equal to 8 .71 meter per second 8 .7 1 meter per second and a narrow end of the cylinder that is diameter so diameter d which is equal to 2 .12 2 .12 centimeter and the whereas the here wider end of the diameter so this is a diameter has a cylinder end so here this is a diameter at narrow end so here is the suppose that is denoted by d1 and now understand that the diameter that is 2 .12 and diameter is 3 .20 that's wider range here at 3 .20 22 d2 is here is 3 .22 at wider range now here in this question we are given a drag force the drag force fd which is equal we can write 1 divided by 2 row multiple we can write a multiple we can write the tau we can say and v square now here in this question we want to find the drag coefficient so here we we want to find this is our drag coefficient that is drag that is drag coefficient that we want to find here so let's solve this question and find out the answer so how to find this this formula and we just simplify and we can write the gamma which is equal to 2 here drag coefficient which is equal you can write 2 multiplied by fd divided by we can write is row here we square multiple by we can write a and we just simplify then we can write the drag coefficient which is equal to we can write 2 multiple we can write here fd which is equal to 12 that force we are given here that is the 27 .6 divided by we can write value of row which is equal to 1000 now value of velocity here so value of velocity we are given 8 .71 so value of velocity 8 .71 and the area so let's write the value of the area so here we can wait let's find to the area radius first so radius which is equal we can make the d1 divided by 2 and and here we are given in 2 .12 centimeters.

02:45 So we are converted in a meter.

02:46 So here we can write, we substitute value and we can write here, answer is 0 .0, 106 meter.

02:52 And for the radius, r2, which is equal to we can write d2 divided by 2, which is substitute value and we just simplify...

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