00:01
Hello students, to solve this question, so first let the mass of b, so this will be m b and mass for a is m a.
00:17
Now we can write all the vertical forces, vertical forces in terms of m a, m b and g, g is the acceleration due to gravity.
00:33
So we can write d is equal to m b g.
00:38
So since there is no vertical acceleration, so net vertical force on b is zero.
00:56
So we can write c will be equal to d that is m b g.
01:03
Now since weight of b is acts normally normally downwards, downwards on a.
01:19
So the normal force, normal force on a by b, so the force p.
01:31
So just the weight of b, p will be equal to m g and l is equal to m a g.
01:41
Now since there is again no vertical acceleration of a, so the net vertical force, vertical force on a is zero.
02:02
So we can write k will be equal to l plus p that is m a g plus m b g that is m a plus m b with common of g.
02:17
Now since we have all the normal forces, so we can calculate the frictional force.
02:24
So let take mu is the coefficient of kinetic friction, kinetic friction.
02:35
So normal force, normal force on b by a.
02:44
So this will be equal to m b g.
02:49
Also frictional force on b by a.
02:58
So this will be equal to mu c.
03:02
So that is equal to 0 .4 m b g.
03:06
Now normal force, normal force on a by b.
03:15
So this is m b g.
03:20
So frictional force, frictional force on a by b, j...