Question

A two wire 400 m long distributor is loaded as follows: Meters from feed point | 100 | 200 | 275 | 325 | 400 Load (A) | 25 | 10 | 30 | 50 | 20 If the resistivity of conductor is 1.5x10^-8 ?-m, what must be the cross-section of the conductor, in order that the voltage drop may not exceed 10 V.

          A two wire 400 m long distributor is loaded as follows:

Meters from feed point | 100 | 200 | 275 | 325 | 400
Load (A) | 25 | 10 | 30 | 50 | 20

If the resistivity of conductor is 1.5x10^-8 ?-m, what must be the cross-section of the conductor, in order that the voltage drop may not exceed 10 V.

A two wire 400 m long distributor is loaded as follows:

Meters from feed point | 100 | 200 | 275 | 325 | 400
Load (A) | 25 | 10 | 30 | 50 | 20

If the resistivity of conductor is 1.5x10^-8 ?-m, what must be the cross-section of the conductor, in order that the voltage drop may not exceed 10 V.

Added by Clinton M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/24/2023

Step 1

The resistance \( R \) of a conductor is given by: \[ R = \rho \frac{L}{A} \] where: - \( \rho \) is the resistivity of the conductor (\(1.5 \times 10^{-8} \, \Omega \cdot m\)), - \( L \) is the length of the conductor (400 m), - \( A \) is the cross-sectional Show more…

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