The period-luminosity relationship for Type II Cepheids is given by:
$M = -2.81 \log P + 17.90$
where $P$ is the pulsation period in days. Plugging in the given period of 10 days, we get:
$M = -2.81 \log (10) + 17.90$
$M = -2.81 (1) + 17.90$
$M = 15.09$
Now
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