Question

Half - Reaction CoO$_2$ + Li$^+$ + e $\leftrightarrow$ LiCoO$_2$ +1V Li$^+$ + C$_6$ + e $\leftrightarrow$ LiC$_6$ -3V Full - Reaction CoO$_2$ + LiC$_6 \implies$ LiCoO$_2$ + C$_6$

          Half - Reaction
CoO$_2$ + Li$^+$ + e $\leftrightarrow$ LiCoO$_2$  +1V
Li$^+$ + C$_6$ + e $\leftrightarrow$ LiC$_6$  -3V
Full - Reaction
CoO$_2$ + LiC$_6 \implies$ LiCoO$_2$ + C$_6$

Half - Reaction
CoO2 + Li^+ + e ↔ LiCoO2 +1V
Li^+ + C6 + e ↔ LiC6 -3V
Full - Reaction
CoO2 + LiC6 LiCoO2 + C6

Added by Andrea V.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Nicole Krahulik

Step 1

Step 1: Analyze the given half-reactions and identify the oxidation and reduction processes: - First half-reaction: CoO₂ + Li⁺ + e⁻ ⇌ LiCoO₂ (+1V) - Second half-reaction: Li⁺ + C₆ + e⁻ ⇌ LiC₆ (-3V) Show more…

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A typical Lithium-Ion battery uses Lithium Cobalt Dioxide and Carbon as cathode and anode respectively. The reaction during discharge is as follows: Given the masses of Co is 59g, Li is 7g, O is 16g, C is 12 and Faraday Constant is 96500 C/mole. Calculate: i. The Open circuit cell voltage, Eoc ii. The free energy change, âˆ†G iii. The theoretical specific energy. Half Reaction: CoO2 + Li + e- -> LiCoO2 + C6 LiCoO2 -> LiC6 +1V 3V Full Reaction: CoO2 + LiC6 -> LiCoO2 + C6