A typical muscle fiber is 2.0 cm long and has a cross-section area of 3.1 x 10-9 m2. When the muscle fiber is stimulated, it pulls with a force of 1.2 mN. What is the work done by the muscle fiber as it contracts to a length of 1.6 cm?
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0 cm and length L2 = 1.6 cm Initial displacement d = L1 - L2 = 2.0 cm - 1.6 cm = 0.4 cm = 0.004 m Show more…
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