00:02
So we're given this information right here in the problem, and we need to construct a large array diagram.
00:08
So i started it right here with the object, being the candle, the position where it's at, your focal length, and this is going to be where your image is going to be created somewhere in this space.
00:19
And we need to find the position.
00:21
First, let's go ahead and find the position of the image.
00:24
So i'm going to call that d .i.
00:26
So you know the equation 1 over the focal length is equal to 1 over the object position plus 1 over the image position.
00:33
So if you rewrite it for just the image position, you end up getting one over the focal length minus one over the object position, which results in approximately 19 meters.
00:46
Or when you solve it for image position, it's going to be 5 .3 centimeters.
00:53
So that's going to be your new image position.
00:55
Now, if you solve for the height, the image height, so you get magnitude.
01:01
So this equation is known.
01:02
So you know that the magnitude is going to be the ratio between the positions, the opposite of the ratio of the positions, negative the ratio of the positions, or just the ratio of heights...