00:01
Hello, in the question we have given that a uniform electric field of 240 newton per coulomb is directed to right.
00:09
So, the electric field is given that is 240 newton per coulomb and it is towards the right.
00:18
So, i will be writing it as x cap.
00:20
So, i will be considering it as moving in the x direction.
00:25
So, a particle with charge, so this charge is given that is minus 6 .2 nano coulomb moves in this field along the path from b to a.
00:51
So, in the first part we have to find out the electric force.
00:57
So, we need to find out this force.
00:59
So, this force will be equal to q times e.
01:07
So, this force will be q is minus 6 .2 into 10 raised to minus 9 into this electric field which is 240.
01:22
So, this is in coulombs and this is in newton per coulomb.
01:28
So, this coulomb coulomb will go away and this is in the x cap direction.
01:33
So, from here this force will turn out to be how much? 1488 into 10 raised to minus 9 newton's but in the minus x cap direction.
01:48
See this minus sign absorbed in the direction.
01:52
So, it is going in the negative.
01:59
So, this is the force.
02:03
Now what we have to do is in the second part we have to find out the potential difference.
02:10
So, we need to find out the potential difference.
02:18
So, in order to find out the potential difference, so it will be vb minus va small a because we are moving this particle from a to b, b to a whatever.
02:33
So, this is equal to minus of e times the distance.
02:41
Now in this question, the distance between b to a is not given nor the figure is given.
02:48
So, it is unpredictable what is this distance might be.
02:52
So, i will just give this recipe what to do and from there we can find out this result.
02:58
So, it is minus e is how much? 240 into d.
03:05
So, whatever this length is from b to a...