00:02
Hello guys in this problem we have a 5 meter long ladder the weight of the ladder is 400 newtons the ladder is uniform therefore the weight act through its center along the vertically downward direction that is w of 400 newtons a normal force from the smooth vertical wall act to the left direction say this normal force as n1 and the normal force from the the rough horizontal surface and to act along the vertical airport direction.
00:41
To prevent sleeping static friction force, f s, act towards the rightward direction and assume the maximum angle of inclination for the ladder is theta.
00:55
The distance of the weight from the point of support is l over 2.
01:04
Say this point of support as o.
01:09
You can write the equation of the equation of the of motion.
01:14
For equilibrium, the net force along vertically upward direction will be 0.
01:28
We consider along vertically upward as positive y and to the rightward direction as positive x.
01:36
So from this we can write the force n2 equals the weight w, say this as equation 1.
01:47
Again, the net force along x direction will be 0, which gives the force n1 equals the weight w, say this as equation 1...