A uniform rod of length L has a mass per unit length l and area of cross-section A. The elongation in the rod is l due to its own weight if it is suspended from the ceiling of a room. The Young’s modulus of the rod is
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Step 1: Start with the given information: - Length of the rod: L - Mass per unit length of the rod: λ - Area of cross-section of the rod: A - Elongation in the rod due to its own weight: l Show more…
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Aakash G.
A uniform rod of length $L$ has a mass per unit length $\lambda$ and area of cross-section $A .$ The elongation in the rod is $l$ due to its own weight if it is suspended from the ceiling of a room. The Young's modulus of the rod is (A) $\frac{2 \lambda g L^{2}}{A l}$ (B) $\frac{\lambda g L^{2}}{2 A l}$ (C) $\frac{2 \lambda g L}{A l}$ (D) $\frac{\lambda g l^{2}}{A L}$
A uniform rod of length $L$ has a mass per unit length $\lambda$ and area of cross-section $A .$ If the young's modulus of the rod is $Y$, then the elongation in the rod due to its own weight is (a) $\frac{2 \lambda g L^{2}}{\Lambda Y}$ (b) $\frac{\lambda g L^{2}}{\Lambda Y}$ (c) $\frac{\lambda g L^{2}}{4 \Lambda Y}$ (d) $\frac{\lambda g L^{2}}{2 \Lambda Y}$
Solids and Fluids
Section B
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