a v88v source is connected in series with r19 kilo ohms and l45h inductor and the current is all

a) The time constant of the circuit is τ = L/R = 45H/1.9kΩ = 23.68ms. The current in an RL circu

Question

A V=88V source is connected in series with R=1.9 kilohms and L=45H inductor, and the current is allowed to reach its maximum. At time t=0, a switch is thrown that disconnects the voltage source but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 44% of its maximum value, the battery is reconnected into the circuit by reversing the switch. a) At what value of time, t, in milliseconds, does the current reach 81% of its maximum? b) How much energy, in milliseconds, is supplied in total by the battery, both in initially bringing the current to the maximum and in bringing the current back to the 81% level from 44%? Ignore energy dissipated in the resistor during those processes.

          A V=88V source is connected in series with R=1.9 kilohms and L=45H inductor, and the current is allowed to reach its maximum. At time t=0, a switch is thrown that disconnects the voltage source but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 44% of its maximum value, the battery is reconnected into the circuit by reversing the switch.

a) At what value of time, t, in milliseconds, does the current reach 81% of its maximum?
b) How much energy, in milliseconds, is supplied in total by the battery, both in initially bringing the current to the maximum and in bringing the current back to the 81% level from 44%? Ignore energy dissipated in the resistor during those processes.

Added by Keith H.

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