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Hey everyone, welcome back.
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In this question we are given with two different vectors.
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The first vector is a vector which is 5 meter and this is below positive xxx at an angle of 30 degree.
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So this is below 30 degree with the positive xxas.
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And the second vector which is b vector is of 2 meter and this is making 20 degree to left of positive y -axis, to left of positive y x's.
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So in the first part we have to basically draw vectors and find their x and y components.
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So first let us try to locate them.
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Let's say this one is the cartesian plane and in this cartesian plane the first vector is below the xx's positive xx is at an angle of 30 degree.
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So this is a vector of 5 meter and this is making an 30 degree.
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Similarly the second one is making 20 degree angle with the positive y x is in the left.
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So let's say this is b vector of 2 meter and this particular angle is fenty degree.
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Okay, so the if you calculate the x component of the a vector so that is coming out as 5 into cause of 30 degree 5 into cost of 30 degree similarly if we calculate the y component of a vector then this one is coming out as this one is coming out as minus of 30 degree.
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I? minus of 5 into sine 30 degree...