Question

A vertically polarized beam of light of intensity 160 W/m² passes through two polarizers. The first polarizer is making an angle of 60° with its transmission axis and the second one is making an angle of 105° with the initial transmission axis. What is the transmitted intensity of this beam of light (7 points)? n? sin ?? = n? sin ?? (160 W/m²) sin 60° = n? sin (105°) n? = (160 W/m²) sin 60 / sin 105° = 160(0.8660) / 1.2756 = 160(?3/2) / 3

          A vertically polarized beam of light of intensity 160 W/m² passes through two polarizers. The first polarizer is making an angle of 60° with its transmission axis and the second one is making an angle of 105° with the initial transmission axis. What is the transmitted intensity of this beam of light (7 points)?
n? sin ?? = n? sin ??
(160 W/m²) sin 60° = n? sin (105°)
n? = (160 W/m²) sin 60 / sin 105° = 160(0.8660) / 1.2756 = 160(?3/2) / 3

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A vertically polarized beam of light of intensity 160 W/m² passes through two polarizers. The first polarizer is making an angle of 60° with its transmission axis and the second one is making an angle of 105° with the initial transmission axis. What is the transmitted intensity of this beam of light (7 points)?
n? sin ?? = n? sin ??
(160 W/m²) sin 60° = n? sin (105°)
n? = (160 W/m²) sin 60 / sin 105° = 160(0.8660) / 1.2756 = 160(?3/2) / 3

Added by Scott C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

06/12/2023

Step 1

The first polarizer is making an angle of 60 with its transmission axis, which means that only cos(60) = 0.5 of the initial intensity can pass through it. Therefore, the intensity after the first polarizer is 0.5 x 160 = 80 W/m2. Show more…

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A vertically polarized beam of light of intensity 160 W/m^2 passes through two polarizers. The first polarizer is making an angle of 60° with its transmission axis, and the second one is making an angle of 105° with the initial transmission axis. What is the transmitted intensity of this beam of light?

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