A very large capacitor has a uniform charge per area b on one plate and -b on the other. The plates move with speed v in the +z direction. Find B (magnetic field vector) everywhere. Solve with explanation, please.
Added by Ashley F.
Step 1
The plates are moving in the +z direction, so we can use the right-hand rule to determine that the magnetic field will circulate around the direction of motion. Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 72 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A large parallel-plate capacitor with uniform surface charge ̃ on the upper plate and -̃ on the lower plate is moving with constant speed v (see Fig. 1 below). (a) Find the magnetic field between the plates and also above and below them. (b) Find the magnetic force per unit area on the upper plate, including its direction. (c) At what speed v would the magnetic force balance electric force?
Adi S.
A very large parallel-plate capacitor has uniform charge per unit area $+\sigma$ on the upper plate and $-\sigma$ on the lower plate. The plates are horizontal, and both move horizontally with speed $v$ to the right. (a) What is the magnetic field between the plates? (b) What is the magnetic field just above or just below the plates? (c) What are the magnitude and direction of the magnetic force per unit area on the upper plate? (d) At what extrapolated speed $v$ will the plate? Suggestion: Use Ampere's law and choose a path that closes between the plates of the capacitor.
Penny R.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD