A very long, straight horizontal wire carries a current such that 8.25×10^18 electrons per second pass any given point going from west to east. What is the magnitude of the magnetic field this wire produces at a point 5.00 cm directly above it?
Added by Randy G.
Step 1
Given: Number of electrons passing per second = 8.25 x 10^18 electrons Charge of one electron = -1.6 x 10^-19 C Current (I) = (Number of electrons passing per second) x (Charge of one electron) Current (I) = 8.25 x 10^18 x (-1.6 x 10^-19) Current (I) = -1.32 Show more…
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