Question

A very long string with the density of 2.0 g/m is stretched along the x-axis with a tension of 5.0 N. At x = 0 m it is tied to a 100 Hz simple harmonic oscillator that vibrates perpendicular to the string with an amplitude of 2.0 mm. The oscillator is at its maximum positive displacement at t = 0 s. At t = 5.0 ms, what is the string’s displacement at a point 2.7 m from the oscillator?

Name: a very long string with the density of 20 gm is stretched along the x axis with a tension of 50 n at x 0 m it is tied to a 100 hz simple harmonic oscillator that vibrates perpendicular to the string w
Uploaded: 2021-10-25T03:32:05-08:00
Duration: 1 min 39 s
Channel: Narayan Hari
Description: a very long string with the density of 20 gm is stretched along the x axis with a tension of 50 n at x 0 m it is tied to a 100 hz simple harmonic oscillator that vibrates perpendicular to the string w

          A very long string with the density of 2.0 g/m is stretched along the
x-axis with a tension of 5.0 N. At x = 0 m it is tied to a 100 Hz
simple harmonic oscillator that vibrates perpendicular to the string
with an amplitude of 2.0 mm. The oscillator is at its maximum
positive displacement at t = 0 s. At t = 5.0 ms, what is the string’s
displacement at a point 2.7 m from the oscillator?

Added by Lefa L.

Physics for Scientist and Engineers: A Strategic Approach

Randall Knight 2nd Edition

Chapter 21

Instant Answer

Solved by Expert Narayan Hari

10/25/2021

Step 1

Given: Frequency (f) = 100 Hz Velocity (v) = √(T/μ) = √(5/2) = √2.5 = 1.58 m/s k = 2π * 100 / 1.58 k = 12.56 m^-1 Show more…

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A very long string with the density of 2.0 g/m is stretched along the x-axis with a tension of 5.0 N. At x = 0 m it is tied to a 100 Hz simple harmonic oscillator that vibrates perpendicular to the string with an amplitude of 2.0 mm. The oscillator is at its maximum positive displacement at t = 0 s. At t = 5.0 ms, what is the string’s displacement at a point 2.7 m from the oscillator?