A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. How long does he have to get out of the way if the shot was released at a height of 2.20 m, and he is 1.80 m tall?
Added by Emilia M.
Step 1
First, we need to find the maximum height reached by the shot put. We can use the kinematic equation: h = h0 + v0t - 1/2gt^2 where h0 is the initial height (2.20 m), v0 is the initial velocity (11.0 m/s), g is the acceleration due to gravity (-9.81 m/s^2), and t Show more…
Show all steps
Your feedback will help us improve your experience
Ivan Kochetkov and 70 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of $11.0 \mathrm{m} / \mathrm{s}$. How long a time does he have to get out of the way if the shot was released at a height of $2.20 \mathrm{m}$ and he is $1.80 \mathrm{m}$ tall?
thoughtful
Nishant K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD