00:01
In this question, they have given that a vibration isolation unit consists of two blocks of hard rubber and they have given that a force of magnitude p, it is equal to 25 kilo newton, causes a deflection of 1 .5 m m of plate a, b.
00:22
So we have to determine the modulus of rigidity of the rubber used.
00:27
So in this question we have two plate of hard rubber.
00:32
So the force on each plate will be equal to half of the total force.
00:36
That will be half of p.
00:37
It will be equal to 12 .5 multiply by 10 raise to the power 3 newton.
00:44
So this is the force on each plate.
00:47
Now if i find the pressure, so the pressure will be equal to force divided by area, it will be equal to force is 12 .5, multiply by 10 raise to the power.
00:58
3 newton divided by the area it will be equal to 0 .15 m m multiply by 0 .1 and after calculating this we will get that the pressure or it is equal to approximately 833 833 0 .33 3m multiply by 10 raise to the power 3 and this is a kind of stress this is a is a kind of stress now we have to find the modulus of rigidity so we know that we have to find first the ratio of change in length that is delta l divided by capital small l and we know that the deflection is equal to 1 .5 multiply by 10 rich to the power minus 3 because the deflection is given in numerator that is 1 .5 we will divide this with the original length that is equal to 0...