A voltage of "10V" and frequency "1000 Hz" is applied to a "0.1 mu F" capacitor in series with a resistor of "500 Omega." Find the power factor of the circuit and the average power dissipated.
Added by Erin H.
Step 1
First, we need to find the impedance of the circuit. The impedance (Z) is given by the formula: Z = √(R^2 + (1/(2 * π * f * C))^2) where R is the resistance, f is the frequency, and C is the capacitance. Show more…
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