0:00
This one a shot.
00:02
We're told that we have, we're going to find the cu plus concentration.
00:20
I wonder if this is supposed to be 2 plus.
00:25
This is co2.
00:26
There we go.
00:32
The palladium sulfate concentration is 0 .498 molar.
00:41
The measured cell potential is given as 0 .447 volts.
00:57
And we're given the see you.
01:57
Okay, let's give this a shot here.
02:06
So, these are my givens.
02:14
So for my anode and my cathode, i have to write these down or i get confused.
02:30
I'm going to have my, my smaller value will be my anode.
02:44
So that'll be, and that will be negative.
03:15
My cathode will be, so my overall reaction will be, so my e for my cell will be equal to my reduction minus my oxidation, and that will equal my positive 0 .987 minus 0 .521.
04:59
So that'll be 0 .987 plus 0 .521.
05:04
And that will equal 1 .521.
05:05
And that will equal 1 .5 .5.
05:11
08 volts.
05:14
Okay, now let's go to my next page.
05:17
So i know that e for my cell, what i don't know is if i have to square that or not.
06:07
So i'm a little confused by that part now.
06:10
So i've got my e for my cell, which was given as 0 .49, 0 .447 equals 0 .508 minus 0 .05590.
06:39
5992 over...