00:01
So let's extract the information from the given equation.
00:04
First of all, the wave number k from the given equation is there is 0 .55.
00:11
Radion per meter angular frequency omega equals 62 .8 by looking at the equation, radiance per second, and phi, that is simply equal to pi by three radiance.
00:27
Let's start from part a.
00:31
In part a, we have to find the lambda, there is wavelength.
00:38
Wave length is equal to 2 pi divided by k.
00:47
There is the wave number, right? simply 2 pi divided by the value of the k is 0 .55.
00:56
So from here the wavelength equals 11 .4 meters.
01:05
For part b we will go here.
01:08
In part b we have to find the frequency.
01:11
We know that frequency equals the angular frequency divided by 2 pi.
01:20
Angular frequency is given that equals 62 .8 radian per second divided by 2 pi.
01:26
From here frequency equals 10 hertz.
01:30
So in part c, we have to find the time period.
01:38
Time period is basically equal to the reciprocal of the frequency.
01:43
And frequency has already been calculated that is 1 divided by 10.
01:46
So from here, time period equals 0 .1 second.
01:52
So let's move to part number d.
01:54
In part d, we have to find the face constant...