Question

A weight of mass 1.04 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.22 kg and radius 1.32 m. The system is released from rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore friction and drag forces, and assume that the string does not slip. Hint: If the string had 0 length, it would be obvious that the point mass contributes Ipt = mR^2 to the total rotational inertia, since the point mass would be directly stuck on the outside of the pulley. What's the difference if the string has nonzero length, so that the point mass hangs below the pulley as in the diagram? None at all! The pulley can't tell the difference between a point mass attached to it by a 0 length string or a 20 meter long string. All it knows is that there's a point mass m attached to its outer edge.

          A weight of mass 1.04 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.22 kg and radius 1.32 m. The system is released from rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore friction and drag forces, and assume that the string does not slip.
Hint: If the string had 0 length, it would be obvious that the point mass contributes Ipt = mR^2 to the total rotational inertia, since the point mass would be directly stuck on the outside of the pulley. What's the difference if the string has nonzero length, so that the point mass hangs below the pulley as in the diagram? None at all! The pulley can't tell the difference between a point mass attached to it by a 0 length string or a 20 meter long string. All it knows is that there's a point mass m attached to its outer edge.

A weight of mass 1.04 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.22 kg and radius 1.32 m. The system is released from rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore friction and drag forces, and assume that the string does not slip.
Hint: If the string had 0 length, it would be obvious that the point mass contributes Ipt = mR^2 to the total rotational inertia, since the point mass would be directly stuck on the outside of the pulley. What's the difference if the string has nonzero length, so that the point mass hangs below the pulley as in the diagram? None at all! The pulley can't tell the difference between a point mass attached to it by a 0 length string or a 20 meter long string. All it knows is that there's a point mass m attached to its outer edge.

Added by Menaira C.

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