00:01
Hi students, this question, a standing wave is being given and in the first part of the question, we are asked to find out the three longest wavelengths which are taken as lambda 1, lambda 2 and lambda 3 respectively.
00:12
Now for the case of a standing wave, its wavelength is taken as lambda to be equal to twice the value of total length of the string capital letter l divided by the number of nodes which is taken as small letter n, where the value of n can be taken as 1, 2, 3, etc.
00:30
Now when the value of n is taken to be a value of 1, the wavelength lambda 1 is taken as 2 into l divided by 1.
00:37
And in this question, the value of total length l is taken to be 2 .4 meter, the above substituting be get lambda 1 to be equal to 2 into 2 .4 divided by 1, which on simplification gives the value of lambda 1 to be equal to 4 .8 meter.
00:54
Next we can find out the value of lambda 2 for which n will be equal to a value of 2.
01:00
By substituting we get lambda 2 to be equal to 2 into 2 .4 divided by 2 which on simplification gives the value of wavelength lambda 2 to be equal to 2 .4 meter.
01:12
Next we can find out the value of lambda 3 for which n will be equal to a value of 3.
01:18
Therefore we can write that value of lambda 3 will be equal to 2 times the value of 2 .4 divided by which on simplification gives the value of lambda 3 to be equal to 1 .6 meters...