At the equivalence point, the moles of HCN and OH- are equal.
moles of HCN = 0.471 M * 0.0243 L = 0.01144 mol
moles of OH- needed = 0.01144 mol
volume of KOH = moles of OH- / 0.308 M = 0.0371 L
Now, we need to find the concentration of CN- at the equivalence
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