00:01
Now we will discuss a question based on the limiting reagent.
00:04
Here we have provided with mass of h .c .l 3 .27 grams.
00:09
Calcium hydroxide mass 7 .62 grams.
00:12
When these masses of hcl and caoh are combining, what mass of water is produced we have to identify.
00:18
First we will write the stichometric equation.
00:22
This is the stachymetric equation between hcl and calcium hydroxide.
00:28
H .c .l is an acid.
00:29
Calcium hydroxide is a base.
00:31
When these two react, we will react.
00:32
Will get salt calcium chloride and water.
00:35
So first we have to identify the limiting reagent as the masses of two reactants were given.
00:42
Which one is the limiting reagent which one is the excess reagent? first we have to identify.
00:47
Then only we can find the mass of water.
00:49
For binding the limiting reagent we have sequential step.
00:52
The first step we have to identify the number of moles of each reagent.
00:59
So here the number of moles can be calculated by mass by polar mass.
01:02
Mass given is 3 .27 molar mass of h -tl is 36 .45.
01:10
Calcium hydrogen mass given is 7 .62.
01:13
Polar mass of calcium hydroxide is 74 .093.
01:20
By solving this we will get 0 .089 moles of h .l and 0 .102 volts of calcium hydroxide.
01:31
After this we have to find the psychometric coefficient.
01:37
Let's speak.
01:38
Stacometric coefficient means before the equation what are the numbers are presented.
01:42
Let's here is 2.
01:44
Stachymetric coefficient of caoh is 1.
01:47
Now we have to divide the number of moles with staccometric coefficient...