Given:
Radius of the wheel, R = 0.550 m
Initial linear velocity, V_i = 41.0 m/s
Stopping distance, s = 180 m
Using the equation of motion: V_f^2 = V_i^2 + 2as
where V_f = 0 (final velocity as it comes to a stop)
41.0^2 = 0 + 2 * a * 180
1681 = 360a
a = -4.7
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