Question

A wheel of radius 1.40 m and mass 35.0 kg is rolling on a leveled ground without slipping. Its moment of inertia about the axis through its center is 28.0 kg.m2. The wheel (i.e. its center of mass) moves with a speed of 10.0 m/s. What is its rotational kinetic energy? (Hint: using the rolling without slipping to find the angular velocity first)

Name: a wheel of radius 140 m and mass 350 kg is rolling on a leveled ground without slipping its moment of inertia about the axis through its center is 280 kgm2 the wheel ie its center of mass mo 35934
Uploaded: 2023-06-07T21:16:13-08:00
Duration: 1 min 26 s
Channel: Ivan Kochetkov
Description: a wheel of radius 140 m and mass 350 kg is rolling on a leveled ground without slipping its moment of inertia about the axis through its center is 280 kgm2 the wheel ie its center of mass mo 35934

          A wheel of radius 1.40 m and mass 35.0 kg is rolling on a
leveled ground without slipping. Its moment of inertia about the
axis through its center is 28.0 kg.m2. The wheel (i.e. its center
of mass) moves with a speed of 10.0 m/s. What is its rotational
kinetic energy? (Hint: using the rolling without slipping to find
the angular velocity first)

Added by Olga P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

06/07/2023

Step 1

Since the wheel is rolling without slipping, we can use the relationship between linear and angular velocity: v = ωr where v is the linear velocity, ω is the angular velocity, and r is the radius of the wheel. In this case, v = 10.0 m/s and r = 1.40 m, so we Show more…

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A wheel of radius 1.40 m and mass 35.0 kg is rolling on a leveled ground without slipping. Its moment of inertia about the axis through its center is 28.0 kg.m2. The wheel (i.e. its center of mass) moves with a speed of 10.0 m/s. What is its rotational kinetic energy? (Hint: using the rolling without slipping to find the angular velocity first)