00:01
Hey everyone, in this question we are given with the wheel and that wheel is rotating about the horizontal axis passing through the wheel.
00:06
Now a force f is applied on the surface of wheel.
00:10
Now we are given that the radius of wheel is 0 .06 meter further its moment of inertia about this particular axis is 2 .5 kg meter square and its initial angular velocity is 0 because it's starting from rest and the magnitude of force is 5 .5 kg meter square and its initial angular velocity is 0 because it's starting from rest and the magnitude of force is 5.
00:30
5 .5 into t.
00:31
That means the force is depending on the time.
00:35
And in this question we have to find out the magnitude of force when the wheel have traveled an angular displacement of 8 revolutions.
00:46
Now we know that 8 revolutions can be converted into radiance by multiplying it with 2 pi.
00:52
So the value of 16 pi that will come out as 50 .28.
00:59
Radiation this is the angular displacement in terms of radius.
01:08
Okay, so let us try to solve this question as we know that torque can be written as angular moment of inertia into angular acceleration, okay, and torque is nothing but force into the position vector of the point of obligation of force from the excess of rotation, that is r, that is equals to moment of inertia i into angular acceleration can be written as rate of change of angular velocity with respect to time...