A wire having a mass per unit length of 0.480 g/cm carries a 1.50 A current horizontally to the south. What are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward?_____________T
Added by Frances M.
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Given: \(m = 0.480 \, \text{g/cm} = 0.480 \times 10^{-3} \, \text{kg/m}\) \(I = 1.50 \, \text{A}\) \(g = 9.8 \, \text{m/s}^2\) Show more…
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