Question

A wire loop with a 2.1-cm-diameter coil is at an angle with a vertical magnetic field. The angle of the normal of the loop to the magnetic field is θ = 48o. The magnetic field changes from 5 T to 27 T in 1.7 s. What is the magnitude of the emf of the coil? Give your answer in milivolts.

Name: a wire loop with a 21 cm diameter coil is at an angle with a vertical magnetic field the angle of the normal of the loop to the magnetic field is 48o the magnetic field changes from 5 t to 2 58837
Uploaded: 2022-06-07T03:40:18-08:00
Duration: 2 min 40 s
Channel: Ivan Kochetkov
Description: a wire loop with a 21 cm diameter coil is at an angle with a vertical magnetic field the angle of the normal of the loop to the magnetic field is 48o the magnetic field changes from 5 t to 2 58837

          A wire loop with a 2.1-cm-diameter coil is at an angle with a vertical magnetic field. The angle of the normal of the loop to the magnetic field is θ = 48o. The magnetic field changes from 5 T to 27 T in 1.7 s. What is the magnitude of the emf of the coil? Give your answer in milivolts.

Added by Jon J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

06/07/2022

Step 1

- The diameter of the coil is 2.1 cm, so the radius \( r \) is half of that: \[ r = \frac{2.1 \, \text{cm}}{2} = 1.05 \, \text{cm} = 0.0105 \, \text{m} \] - The area \( A \) of the loop is given by the formula for the area of a circle: \[ A = \pi r^2 = Show more…

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A wire loop with a 2.1-cm-diameter coil is at an angle with a vertical magnetic field. The angle of the normal of the loop to the magnetic field is θ = 48o. The magnetic field changes from 5 T to 27 T in 1.7 s. What is the magnitude of the emf of the coil? Give your answer in milivolts.