00:01
Hi, in this question we have the single slit minima.
00:03
So, in case of single slit minima, so by formula of diffraction we have a sin theta is equal to m lambda and for so here we can substitute for sin theta.
00:18
So, sin theta will be equal to m lambda divided by a and we have for part b so or let us have the same part.
00:29
So, this is minima and for single slit maxima.
00:36
So, single slit maxima we have so we can write b sin theta is equal to m lambda or sin theta is m lambda divided by d.
00:50
So, here we have d is less than a then theta is higher for single slit.
00:58
So, theta is higher for grating.
01:01
So, we have for part b we are given with a value of a as 10 micrometer and l is given as 0 .2 meter and bandwidth is given as 1 .6 centimeter.
01:15
So, here we have the value of theta can be given by tan theta is equal to so tan theta is the position of the first minima is given by so position of first minima is equal to 0 .8 centimeter...