A woman of mass 53 kg jumps off the bow of a 46 kg canoe that is initially at rest. If her velocity is 1 m/s to the right, what is the velocity of the canoe after she jumps? Answer in units of m/s.
Added by Encarnacion W.
Step 1
The total momentum before the woman jumps off is given by: Total momentum = (mass of woman * velocity of woman) + (mass of canoe * velocity of canoe) Total momentum = (53 kg * 1 m/s) + (46 kg * 0 m/s) Total momentum = 53 kg*m/s Show more…
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