00:02
Hello guys in this problem we have the volume of the wooden cube equals 5 .24 times 10 to the minus 4 cubic centimeter and the mass of the steel placed on the cube so that the cube is fully submerged inside the water is 0 .31 kilograms.
00:25
Now consider the cube free border diagram on the top of the cube there is a steel placed on the cube.
00:33
Now in this particular situation, the cube is fully submerged in water, then the force is acting on the system are the weight of the cube acting along the vertical downward direction, that is the force of gravity on the cube.
00:49
One more force acting along the vertical downward direction is the weight of the steel mass, that is the force of gravity on the steel, and a buoyant force act on the system along the vertically upward direction.
01:06
Now for fully submerged condition, the net force on the system equals 0, which means the biant force equals the overall weight, that is the weight of the steel plus the weight of the cube.
01:35
The biant force exerted by water equals the density of the water times the volume of the cube times the gravitational acceleration and the weight of the steel equals the mass of the steel times the gravitational acceleration plus the weight of the cube equals the density of the cube times the volume of the cube times the gravitational acceleration.
01:54
Now we can cancel out the gravitational acceleration from each term.
02:01
Then we get the equation for the density of the cube as the density of the water times the volume of the cube minus the mass of the steel over the volume of the cube...